Draw the Bode Diagram for the transfer function:
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Make both the lowest order term in the numerator and denominator unity. The numerator is an order 2 polynomial, the denominator is order 3.
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The transfer function has 4 components:
A constant of 1
A pole at s=-100
A repeated pole at the origin (s=0)
Complex conjugate zeros at the roots of s2+s+25,
with
This is done in the diagram below.
The constant is the cyan line (A quantity of 1 is equal to 0 dB). The phase is constant at 0 degrees.
The pole at 100 rad/sec is the green line. It is 0 dB up to the break frequency, then falls with a slope of -20 dB/dec. The phase is 0 degrees up to 1/10 the break frequency then falls linearly to -90 degrees at 10 times the break frequency.
The repeated poles at the origin are shown with the blue line. The slope is -40 dB/decade (because pole is repeated), and goes through 0 dB at 1 rad/sec. The slope is -180 degrees (again because of double pole).
The complex zero is shown by the red line. The zeros give a dip in the magnitude plot of
at a frequency of 5 rad/sec. This is shown by the red circle. The phase goes from the low frequency asymptote (0 degrees) at
to the high frequency asymptote at
The exact response is the black line.

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Erik Cheever This page may be freely used for educational
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Erik Cheever Department of Engineering Swarthmore College